请问如何获取错误信息并让程序继续进行下去?

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希望能够获得错误类型,然后将错误类型打印出来,然后让程序继续执行余下语句?

谢谢

错误

类型

程序

语句

7 replies • 2016-09-26 14:28:46 +08:00

Livid

MOD

PRO

Sep 25, 2016 via iPhone

try:
except:

及试试这个服务： https://sentry.io

Newyorkcity

Sep 25, 2016

@Livid
try
except
这个我知道,问题在于怎么得到错误信息并且将它赋值给一个变量,方便以后调用..
谢谢

terence4444

Sep 25, 2016 via iPhone

except 下面可以 catch 到错误类型，看下文档去吧

noli

Sep 25, 2016

http://stackoverflow.com/questions/2535760/python-try-except-comma-vs-as-in-except

billlee

Sep 25, 2016

try:
　　...
except Exception:
　　 type, value, traceback = sys.exc_info()
　　 print('{}: {}'.format(type.__name__, value))

cortexm3

Sep 25, 2016

try:
... ...

except Exception as e:
... ...

linzhi

Sep 26, 2016

try:
....
except Exception as e:
print traceback.format_exc()
continue

这样呢