比如像这样的地址用 urllib.request 获取时会报错
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1
ltux May 5, 2017
[urllib.quote()]( https://docs.python.org/2/library/urllib.html#urllib.quote)
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2
noe132 May 5, 2017
unicode 字符应该是要编码成类似%20%20 这样的东西
先把 url 给 encode 一下应该就可以了。 urllib.urlencode(url) |
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3
golmic May 5, 2017
用 requests
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4
owt5008137 May 5, 2017 via Android
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