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angelcstt
V2EX  ›  程序员

各位大佬帮忙做个菊花的笔试题,感谢

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  •   angelcstt · Aug 7, 2019 · 4614 views
    This topic created in 2655 days ago, the information mentioned may be changed or developed.

    RT

    https://i.loli.net/2019/08/07/gS95mI8nbZBX4ha.jpg

    感谢

    18 replies  •  2019-08-08 11:17:37 +08:00
    angelcstt
    angelcstt
    OP
    Aug 7, 2019
    1
    大佬在哪里 求助大佬啊 有偿都可以
    msaionyc
    msaionyc
    Aug 7, 2019
    3
    你题目给完整了吗
    angelcstt
    angelcstt
    OP
    Aug 7, 2019
    4
    @msaionyc 大佬等我拍完整
    wateryessence
    wateryessence
    Aug 7, 2019
    5
    牛客网问去
    angelcstt
    angelcstt
    OP
    Aug 7, 2019
    6
    第一题 @msaionyc ~

    https://i.loli.net (外链)/2019/08/07/gS95mI8nbZBX4ha.jpg
    https://imgchr.com/i/eII5 (外链) GT
    lxy42
    lxy42
    Aug 7, 2019 via Android
    7
    第一题没拍全吧,估计考查的是中缀后缀表达式。
    angelcstt
    angelcstt
    OP
    Aug 7, 2019 via iPhone
    8
    @lxy42 第一题下面补充了大佬
    brainfxxk
    brainfxxk
    Aug 7, 2019
    9
    第一个表达式求值 第二个字符串处理...
    lxy42
    lxy42
    Aug 7, 2019 via Android
    10
    第二题用一个长度为 26 的数组表示字符集,数组元素值等于对应字符的个数。两个数组相减就是结果。
    Leigg
    Leigg
    Aug 7, 2019 via Android
    11
    能不能换个图床,这个很渣
    angelcstt
    angelcstt
    OP
    Aug 7, 2019 via iPhone
    12
    @Leigg 提交了,谢谢啦
    angelcstt
    angelcstt
    OP
    Aug 7, 2019 via iPhone
    13
    @lxy42 谢谢啦
    wangkai0351
    wangkai0351
    Aug 7, 2019
    14
    #include <iostream>
    #include <string>
    #include <map>
    #include <vector>
    #include <sstream>
    #include <string.h>
    using namespace std;

    vector<string> split(const string &str,const string &pattern)
    {
    //const char* convert to char*
    char * strc = new char[strlen(str.c_str())+1];
    strcpy(strc, str.c_str());
    vector<string> resultVec;
    char* tmpStr = strtok(strc, pattern.c_str());
    while (tmpStr != NULL)
    {
    resultVec.push_back(string(tmpStr));
    tmpStr = strtok(NULL, pattern.c_str());
    }

    delete[] strc;

    return resultVec;
    }

    int main(void)
    {
    string s;
    while(cin>>s)
    {
    string s1;
    string s2;
    size_t at_pos = s.find('@');
    //cout << "at_pos = " << at_pos << endl;
    if(at_pos == s.size()-1)
    {
    for (int i = 0; i < s.size()-1; ++i) {
    cout << s[i];
    }
    cout << endl;
    break;
    }
    else
    {
    s1 = s.substr(0,at_pos);
    s2 = s.substr(at_pos+1,s.size());
    //cout << s1 << endl;
    //cout << s2 << endl;
    }
    //分别处理 s1,s2
    map<char,int> um1;
    map<char,int> um2;
    //s1 按照逗号分割
    vector<string> v1;
    v1 = split(s1,",");
    for(auto e:v1)
    {
    int i;
    char c;
    char c_;
    stringstream ss(e);
    ss >> c >> c_ >> i;
    //cout << "c = " << c << " i = " << i << endl;
    um1[c] = i;
    }
    //s2 按照逗号分割
    vector<string> v2;
    v2 = split(s2,",");
    for(auto e:v2)
    {
    int i;
    char c;
    char c_;
    stringstream ss(e);
    ss >> c >> c_ >> i;
    //cout << "c = " << c << " i = " << i << endl;
    um2[c] = i;
    }
    string res;
    for(auto e:um1)
    {
    res += e.first;
    res += ":";
    res += to_string(e.second-um2[e.first]);
    res += ",";
    }
    for (int j = 0; j < res.size()-1; ++j) {
    cout << res[j];
    }
    cout << endl;
    }
    return 0;
    }
    //a:3,b:5,c:1@
    //a:3,b:5,c:2@a:1,b:2
    wangkai0351
    wangkai0351
    Aug 7, 2019
    15
    zhoudaiyu
    zhoudaiyu
    Aug 7, 2019
    16
    我来发个第一题的,不知道能不能用 Py 实现
    def get_result(given_string):
    return eval((" ".join([items for items in given_string]).replace("1", "True").replace("0", "False").replace("!", "not").replace("&", "and").replace("|", "or")))
    Mountain
    Mountain
    Aug 8, 2019 via iPhone
    17
    公然求助场外观众了?
    summer20100514
    summer20100514
    Aug 8, 2019
    18
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