//匿名内部类：
Runnable r = new Runnable() {
@Override
public void run() {
}
};
//改写成 lambda 表达式：
Runnable r = new Runnable(()->{});
无法通过编译，提示“'Runnable' is abstract; cannot be instantiated”
请问问题出在哪，非常感谢~This topic created in 2054 days ago, the information mentioned may be changed or developed.
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1
Runnable r = () -> {};
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1 |
2
@nthin0 谢谢大佬，但是为啥不用写 new runnable()啊
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ninjachenMar 26, 2021
3
因为它不是 lambda 表达式
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brustMar 27, 2021
4
Runnable r = ()->{};
Thread t = new Thread(new Runnable() { @Override public void run() { } }); Thread t = new Thread(()->{}); |
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zm8m93Q1e5otOC69Mar 29, 2021
5
不用加 new 了吧 ()->{}就是 new 了
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